Solve -3/2y+18geqy/2

$$- \frac { 3 } { 2 } y + 18 \geq \frac { y } { 2 }$$

Solve for y

$$y\leq 9$$

Solution Steps

Multiply both sides of the equation by 2. Since 2 is positive, the inequality direction remains the same.

$$-3y+36\geq y$$

Subtract y from both sides.

$$-3y+36-y\geq 0$$

Combine -3y and -y to get -4y.

$$-4y+36\geq 0$$

Subtract 36 from both sides. Anything subtracted from zero gives its negation.

$$-4y\geq -36$$

Divide both sides by -4. Since -4 is negative, the inequality direction is changed.

$$y\leq \frac{-36}{-4}$$

Divide -36 by -4 to get 9.

$$y\leq 9$$