Solve -3/2+(-0,7)=-3/2-7/10=-15-7/10-frac{12}{10}=

$$- \frac { 3 } { 2 } + ( - 0,7 ) = - \frac { 3 } { 2 } - \frac { 7 } { 10 } = \frac { - 15 - 7 } { 10 } - \frac { 12 } { 10 } =$$

Verify

Solution Steps

Convert decimal number 0,7 to fraction \frac{7}{10}.

$$-\frac{3}{2}-\frac{7}{10}=-\frac{3}{2}-\frac{7}{10}\text{ and }-\frac{3}{2}-\frac{7}{10}=\frac{-15-7}{10}-\frac{12}{10}$$

Least common multiple of 2 and 10 is 10. Convert -\frac{3}{2} and \frac{7}{10} to fractions with denominator 10.

$$-\frac{15}{10}-\frac{7}{10}=-\frac{3}{2}-\frac{7}{10}\text{ and }-\frac{3}{2}-\frac{7}{10}=\frac{-15-7}{10}-\frac{12}{10}$$

Since -\frac{15}{10} and \frac{7}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-15-7}{10}=-\frac{3}{2}-\frac{7}{10}\text{ and }-\frac{3}{2}-\frac{7}{10}=\frac{-15-7}{10}-\frac{12}{10}$$

Subtract 7 from -15 to get -22.

$$\frac{-22}{10}=-\frac{3}{2}-\frac{7}{10}\text{ and }-\frac{3}{2}-\frac{7}{10}=\frac{-15-7}{10}-\frac{12}{10}$$

Reduce the fraction \frac{-22}{10} to lowest terms by extracting and canceling out 2.

$$-\frac{11}{5}=-\frac{3}{2}-\frac{7}{10}\text{ and }-\frac{3}{2}-\frac{7}{10}=\frac{-15-7}{10}-\frac{12}{10}$$

Least common multiple of 2 and 10 is 10. Convert -\frac{3}{2} and \frac{7}{10} to fractions with denominator 10.

$$-\frac{11}{5}=-\frac{15}{10}-\frac{7}{10}\text{ and }-\frac{3}{2}-\frac{7}{10}=\frac{-15-7}{10}-\frac{12}{10}$$

Since -\frac{15}{10} and \frac{7}{10} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{11}{5}=\frac{-15-7}{10}\text{ and }-\frac{3}{2}-\frac{7}{10}=\frac{-15-7}{10}-\frac{12}{10}$$

Subtract 7 from -15 to get -22.

$$-\frac{11}{5}=\frac{-22}{10}\text{ and }-\frac{3}{2}-\frac{7}{10}=\frac{-15-7}{10}-\frac{12}{10}$$

Reduce the fraction \frac{-22}{10} to lowest terms by extracting and canceling out 2.

$$-\frac{11}{5}=-\frac{11}{5}\text{ and }-\frac{3}{2}-\frac{7}{10}=\frac{-15-7}{10}-\frac{12}{10}$$

Compare -\frac{11}{5} and -\frac{11}{5}.

$$\text{true}\text{ and }-\frac{3}{2}-\frac{7}{10}=\frac{-15-7}{10}-\frac{12}{10}$$

Least common multiple of 2 and 10 is 10. Convert -\frac{3}{2} and \frac{7}{10} to fractions with denominator 10.

$$\text{true}\text{ and }-\frac{15}{10}-\frac{7}{10}=\frac{-15-7}{10}-\frac{12}{10}$$

Since -\frac{15}{10} and \frac{7}{10} have the same denominator, subtract them by subtracting their numerators.

$$\text{true}\text{ and }\frac{-15-7}{10}=\frac{-15-7}{10}-\frac{12}{10}$$

Subtract 7 from -15 to get -22.

$$\text{true}\text{ and }\frac{-22}{10}=\frac{-15-7}{10}-\frac{12}{10}$$

Reduce the fraction \frac{-22}{10} to lowest terms by extracting and canceling out 2.

$$\text{true}\text{ and }-\frac{11}{5}=\frac{-15-7}{10}-\frac{12}{10}$$

Subtract 7 from -15 to get -22.

$$\text{true}\text{ and }-\frac{11}{5}=\frac{-22}{10}-\frac{12}{10}$$

Reduce the fraction \frac{-22}{10} to lowest terms by extracting and canceling out 2.

$$\text{true}\text{ and }-\frac{11}{5}=-\frac{11}{5}-\frac{12}{10}$$

Reduce the fraction \frac{12}{10} to lowest terms by extracting and canceling out 2.

$$\text{true}\text{ and }-\frac{11}{5}=-\frac{11}{5}-\frac{6}{5}$$

Since -\frac{11}{5} and \frac{6}{5} have the same denominator, subtract them by subtracting their numerators.

$$\text{true}\text{ and }-\frac{11}{5}=\frac{-11-6}{5}$$

Subtract 6 from -11 to get -17.

$$\text{true}\text{ and }-\frac{11}{5}=-\frac{17}{5}$$

Compare -\frac{11}{5} and -\frac{17}{5}.

$$\text{true}\text{ and }\text{false}$$

The conjunction of \text{true} and \text{false} is \text{false}.

$$\text{false}$$