Solve -2z/3+2kz

$$- \frac { 2 z } { 3 } + 2 k z$$

Evaluate

$$2kz-\frac{2z}{3}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 2kz times \frac{3}{3}.

$$-\frac{2z}{3}+\frac{3\times 2kz}{3}$$

Since -\frac{2z}{3} and \frac{3\times 2kz}{3} have the same denominator, add them by adding their numerators.

$$\frac{-2z+3\times 2kz}{3}$$

Do the multiplications in -2z+3\times 2kz.

$$\frac{-2z+6kz}{3}$$

Factor

$$\frac{2z\left(3k-1\right)}{3}$$

Solution Steps

Factor out \frac{2}{3}.

$$\frac{2\left(-z+3kz\right)}{3}$$

Consider -z+3kz. Factor out z.

$$z\left(-1+3k\right)$$

Rewrite the complete factored expression.

$$\frac{2z\left(3k-1\right)}{3}$$