Solve -2/3x-5y+1=0

$$- \frac { 2 } { 3 } x - 5 y + 1 = 0$$

Solve for x

$$x=\frac{3-15y}{2}$$

Steps for Solving Linear Equation

Add 5y to both sides. Anything plus zero gives itself.

$$-\frac{2}{3}x+1=5y$$

Subtract 1 from both sides.

$$-\frac{2}{3}x=5y-1$$

Divide both sides of the equation by -\frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{2}{3}x}{-\frac{2}{3}}=\frac{5y-1}{-\frac{2}{3}}$$

Dividing by -\frac{2}{3} undoes the multiplication by -\frac{2}{3}.

$$x=\frac{5y-1}{-\frac{2}{3}}$$

Divide 5y-1 by -\frac{2}{3} by multiplying 5y-1 by the reciprocal of -\frac{2}{3}.

$$x=\frac{3-15y}{2}$$

Solve for y

$$y=-\frac{2x}{15}+\frac{1}{5}$$

Steps for Solving Linear Equation

Add \frac{2}{3}x to both sides. Anything plus zero gives itself.

$$-5y+1=\frac{2}{3}x$$

Subtract 1 from both sides.

$$-5y=\frac{2}{3}x-1$$

The equation is in standard form.

$$-5y=\frac{2x}{3}-1$$

Divide both sides by -5.

$$\frac{-5y}{-5}=\frac{\frac{2x}{3}-1}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$y=\frac{\frac{2x}{3}-1}{-5}$$

Divide \frac{2x}{3}-1 by -5.

$$y=-\frac{2x}{15}+\frac{1}{5}$$