Solve -2/3x(11/8)^2+1/3x11/8+2

$$- \frac { 2 } { 3 } x ( \frac { 11 } { 8 } ) ^ { 2 } + \frac { 1 } { 3 } x \frac { 11 } { 8 } + 2$$

Evaluate

$$-\frac{77x}{96}+2$$

Solution Steps

Calculate \frac{11}{8} to the power of 2 and get \frac{121}{64}.

$$-\frac{2}{3}x\times \frac{121}{64}+\frac{1}{3}x\times \frac{11}{8}+2$$

Multiply -\frac{2}{3} times \frac{121}{64} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-2\times 121}{3\times 64}x+\frac{1}{3}x\times \frac{11}{8}+2$$

Do the multiplications in the fraction \frac{-2\times 121}{3\times 64}.

$$\frac{-242}{192}x+\frac{1}{3}x\times \frac{11}{8}+2$$

Reduce the fraction \frac{-242}{192} to lowest terms by extracting and canceling out 2.

$$-\frac{121}{96}x+\frac{1}{3}x\times \frac{11}{8}+2$$

Multiply \frac{1}{3} times \frac{11}{8} by multiplying numerator times numerator and denominator times denominator.

$$-\frac{121}{96}x+\frac{1\times 11}{3\times 8}x+2$$

Do the multiplications in the fraction \frac{1\times 11}{3\times 8}.

$$-\frac{121}{96}x+\frac{11}{24}x+2$$

Combine -\frac{121}{96}x and \frac{11}{24}x to get -\frac{77}{96}x.

$$-\frac{77}{96}x+2$$

Factor

$$\frac{192-77x}{96}$$

Solution Steps

Factor out \frac{1}{96}.

$$\frac{-121x+44x+192}{96}$$

Consider -121x+44x+192. Multiply and combine like terms.

$$-77x+192$$

Rewrite the complete factored expression.

$$\frac{-77x+192}{96}$$