Solve -2/3x+1leq2x+2

$$- \frac { 2 } { 3 } x + 1 \leq 2 x + 2$$

Solve for x

$$x\geq -\frac{3}{8}$$

Solution Steps

Subtract 2x from both sides.

$$-\frac{2}{3}x+1-2x\leq 2$$

Combine -\frac{2}{3}x and -2x to get -\frac{8}{3}x.

$$-\frac{8}{3}x+1\leq 2$$

Subtract 1 from both sides.

$$-\frac{8}{3}x\leq 2-1$$

Subtract 1 from 2 to get 1.

$$-\frac{8}{3}x\leq 1$$

Multiply both sides by -\frac{3}{8}, the reciprocal of -\frac{8}{3}. Since -\frac{8}{3} is negative, the inequality direction is changed.

$$x\geq 1\left(-\frac{3}{8}\right)$$

Multiply 1 and -\frac{3}{8} to get -\frac{3}{8}.

$$x\geq -\frac{3}{8}$$