Solve -2/3(-3/2a+3/8)=

$$- \frac { 2 } { 3 } ( - \frac { 3 } { 2 } a + \frac { 3 } { 8 } ) =$$

Evaluate

$$a = -\frac{1}{4} = -0.25$$

Solution Steps

Use the distributive property to multiply -\frac{2}{3} by -\frac{3}{2}a+\frac{3}{8}.

$$-\frac{2}{3}\left(-\frac{3}{2}\right)a-\frac{2}{3}\times \frac{3}{8}$$

Multiply -\frac{2}{3} times -\frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-2\left(-3\right)}{3\times 2}a-\frac{2}{3}\times \frac{3}{8}$$

Do the multiplications in the fraction \frac{-2\left(-3\right)}{3\times 2}.

$$\frac{6}{6}a-\frac{2}{3}\times \frac{3}{8}$$

Divide 6 by 6 to get 1.

$$1a-\frac{2}{3}\times \frac{3}{8}$$

Multiply -\frac{2}{3} times \frac{3}{8} by multiplying numerator times numerator and denominator times denominator.

$$1a+\frac{-2\times 3}{3\times 8}$$

Cancel out 3 in both numerator and denominator.

$$1a+\frac{-2}{8}$$

Reduce the fraction \frac{-2}{8} to lowest terms by extracting and canceling out 2.

$$1a-\frac{1}{4}$$

For any term t, t\times 1=t and 1t=t.

$$a-\frac{1}{4}$$

Expand

$$a = -\frac{1}{4} = -0.25$$

Solution Steps

Use the distributive property to multiply -\frac{2}{3} by -\frac{3}{2}a+\frac{3}{8}.

$$-\frac{2}{3}\left(-\frac{3}{2}\right)a-\frac{2}{3}\times \frac{3}{8}$$

Multiply -\frac{2}{3} times -\frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-2\left(-3\right)}{3\times 2}a-\frac{2}{3}\times \frac{3}{8}$$

Do the multiplications in the fraction \frac{-2\left(-3\right)}{3\times 2}.

$$\frac{6}{6}a-\frac{2}{3}\times \frac{3}{8}$$

Divide 6 by 6 to get 1.

$$1a-\frac{2}{3}\times \frac{3}{8}$$

Multiply -\frac{2}{3} times \frac{3}{8} by multiplying numerator times numerator and denominator times denominator.

$$1a+\frac{-2\times 3}{3\times 8}$$

Cancel out 3 in both numerator and denominator.

$$1a+\frac{-2}{8}$$

Reduce the fraction \frac{-2}{8} to lowest terms by extracting and canceling out 2.

$$1a-\frac{1}{4}$$

For any term t, t\times 1=t and 1t=t.

$$a-\frac{1}{4}$$