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-\frac{2}{3}\left(\frac{3-5}{2}+\frac{7}{2}\right)
Since \frac{3}{2} and \frac{5}{2} have the same denominator, subtract them by subtracting their numerators.
-\frac{2}{3}\left(\frac{-2}{2}+\frac{7}{2}\right)
Subtract 5 from 3 to get -2.
-\frac{2}{3}\left(-1+\frac{7}{2}\right)
Divide -2 by 2 to get -1.
-\frac{2}{3}\left(-\frac{2}{2}+\frac{7}{2}\right)
Convert -1 to fraction -\frac{2}{2}.
-\frac{2}{3}\times \frac{-2+7}{2}
Since -\frac{2}{2} and \frac{7}{2} have the same denominator, add them by adding their numerators.
-\frac{2}{3}\times \frac{5}{2}
Add -2 and 7 to get 5.
\frac{-2\times 5}{3\times 2}
Multiply -\frac{2}{3} times \frac{5}{2} by multiplying numerator times numerator and denominator times denominator.
\frac{-10}{6}
Do the multiplications in the fraction \frac{-2\times 5}{3\times 2}.
-\frac{5}{3}
Reduce the fraction \frac{-10}{6} to lowest terms by extracting and canceling out 2.