Solve -2/3+[3/8*(-4/9)]=

$$- \frac { 2 } { 3 } + [ \frac { 3 } { 8 } \times ( - \frac { 4 } { 9 } ) ] =$$

Evaluate

$$-\frac{5}{6}\approx -0.833333333$$

Solution Steps

Multiply \frac{3}{8} times -\frac{4}{9} by multiplying numerator times numerator and denominator times denominator.

$$-\frac{2}{3}+\frac{3\left(-4\right)}{8\times 9}$$

Do the multiplications in the fraction \frac{3\left(-4\right)}{8\times 9}.

$$-\frac{2}{3}+\frac{-12}{72}$$

Reduce the fraction \frac{-12}{72} to lowest terms by extracting and canceling out 12.

$$-\frac{2}{3}-\frac{1}{6}$$

Least common multiple of 3 and 6 is 6. Convert -\frac{2}{3} and \frac{1}{6} to fractions with denominator 6.

$$-\frac{4}{6}-\frac{1}{6}$$

Since -\frac{4}{6} and \frac{1}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-4-1}{6}$$

Subtract 1 from -4 to get -5.

$$-\frac{5}{6}$$

Factor

$$-\frac{5}{6} = -0.8333333333333334$$