Solve -frac{2sqrt{3}}{3}*16+frac{sqrt{3}}{3}*4=

$$- \frac { 2 \sqrt { 3 } } { 3 } \times 16 + \frac { \sqrt { 3 } } { 3 } \times 4 =$$

Evaluate

$$-\frac{28\sqrt{3}}{3}\approx -16.165807537$$

Short Solution Steps

Express 16\left(-\frac{2\sqrt{3}}{3}\right) as a single fraction.

$$\frac{-16\times 2\sqrt{3}}{3}+4\times \frac{\sqrt{3}}{3}$$

Express 4\times \frac{\sqrt{3}}{3} as a single fraction.

$$\frac{-16\times 2\sqrt{3}}{3}+\frac{4\sqrt{3}}{3}$$

Since \frac{-16\times 2\sqrt{3}}{3} and \frac{4\sqrt{3}}{3} have the same denominator, add them by adding their numerators.

$$\frac{-16\times 2\sqrt{3}+4\sqrt{3}}{3}$$

Do the multiplications in -16\times 2\sqrt{3}+4\sqrt{3}.

$$\frac{-32\sqrt{3}+4\sqrt{3}}{3}$$

Do the calculations in -32\sqrt{3}+4\sqrt{3}.

$$\frac{-28\sqrt{3}}{3}$$