Solve -16/9=-4/3(5/3divn)

$$- \frac { 16 } { 9 } = - \frac { 4 } { 3 } ( \frac { 5 } { 3 } \div n )$$

Solve for n

$$n = \frac{5}{4} = 1\frac{1}{4} = 1.25$$

Steps for Solving Linear Equation

Multiply both sides by -\frac{3}{4}, the reciprocal of -\frac{4}{3}.

$$-\frac{16}{9}\left(-\frac{3}{4}\right)=\frac{\frac{5}{3}}{n}$$

Multiply -\frac{16}{9} times -\frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-16\left(-3\right)}{9\times 4}=\frac{\frac{5}{3}}{n}$$

Do the multiplications in the fraction \frac{-16\left(-3\right)}{9\times 4}.

$$\frac{48}{36}=\frac{\frac{5}{3}}{n}$$

Reduce the fraction \frac{48}{36} to lowest terms by extracting and canceling out 12.

$$\frac{4}{3}=\frac{\frac{5}{3}}{n}$$

Variable n cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 3n, the least common multiple of 3,n.

$$4n=3\times \frac{5}{3}$$

Cancel out 3 and 3.

$$4n=5$$

Divide both sides by 4.

$$n=\frac{5}{4}$$