Solve -1/6*(6-18)-12*1/3=

$$- \frac { 1 } { 6 } \cdot ( 6 - 18 ) - 12 \cdot \frac { 1 } { 3 } =$$

Evaluate

$$-2$$

Solution Steps

Subtract 18 from 6 to get -12.

$$-\frac{1}{6}\left(-12\right)-12\times \frac{1}{3}$$

Express -\frac{1}{6}\left(-12\right) as a single fraction.

$$\frac{-\left(-12\right)}{6}-12\times \frac{1}{3}$$

Multiply -1 and -12 to get 12.

$$\frac{12}{6}-12\times \frac{1}{3}$$

Divide 12 by 6 to get 2.

$$2-12\times \frac{1}{3}$$

Multiply 12 and \frac{1}{3} to get \frac{12}{3}.

$$2-\frac{12}{3}$$

Divide 12 by 3 to get 4.

$$2-4$$

Subtract 4 from 2 to get -2.

$$-2$$

Factor

$$-2$$