Solve -1/5-(-2/3)^2*(-1/2)

$$- \frac { 1 } { 5 } - ( - \frac { 2 } { 3 } ) ^ { 2 } \times ( - \frac { 1 } { 2 } )$$

Evaluate

$$\frac{1}{45}\approx 0.022222222$$

Solution Steps

Calculate -\frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$-\frac{1}{5}-\frac{4}{9}\left(-\frac{1}{2}\right)$$

Multiply \frac{4}{9} times -\frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$-\frac{1}{5}-\frac{4\left(-1\right)}{9\times 2}$$

Do the multiplications in the fraction \frac{4\left(-1\right)}{9\times 2}.

$$-\frac{1}{5}-\frac{-4}{18}$$

Reduce the fraction \frac{-4}{18} to lowest terms by extracting and canceling out 2.

$$-\frac{1}{5}-\left(-\frac{2}{9}\right)$$

The opposite of -\frac{2}{9} is \frac{2}{9}.

$$-\frac{1}{5}+\frac{2}{9}$$

Least common multiple of 5 and 9 is 45. Convert -\frac{1}{5} and \frac{2}{9} to fractions with denominator 45.

$$-\frac{9}{45}+\frac{10}{45}$$

Since -\frac{9}{45} and \frac{10}{45} have the same denominator, add them by adding their numerators.

$$\frac{-9+10}{45}$$

Add -9 and 10 to get 1.

$$\frac{1}{45}$$

Factor

$$\frac{1}{3 ^ {2} \cdot 5} = 0.022222222222222223$$