Solve -1/4a+2b^2+6a-1/2a+1/3b^2-6a

$$- \frac { 1 } { 4 } a + 2 b ^ { 2 } + 6 a - \frac { 1 } { 2 } a + \frac { 1 } { 3 } b ^ { 2 } - 6 a$$

Evaluate

$$\frac{7b^{2}}{3}-\frac{3a}{4}$$

Solution Steps

Combine -\frac{1}{4}a and 6a to get \frac{23}{4}a.

$$\frac{23}{4}a+2b^{2}-\frac{1}{2}a+\frac{1}{3}b^{2}-6a$$

Combine \frac{23}{4}a and -\frac{1}{2}a to get \frac{21}{4}a.

$$\frac{21}{4}a+2b^{2}+\frac{1}{3}b^{2}-6a$$

Combine 2b^{2} and \frac{1}{3}b^{2} to get \frac{7}{3}b^{2}.

$$\frac{21}{4}a+\frac{7}{3}b^{2}-6a$$

Combine \frac{21}{4}a and -6a to get -\frac{3}{4}a.

$$-\frac{3}{4}a+\frac{7}{3}b^{2}$$

Factor

$$\frac{28b^{2}-9a}{12}$$

Solution Steps

Factor out \frac{1}{12}.

$$\frac{-3a+24b^{2}+72a-6a+4b^{2}-72a}{12}$$