Solve -1/3(p-3)-1/4(10-p)=0

$$- \frac { 1 } { 3 } ( p - 3 ) - \frac { 1 } { 4 } ( 10 - p ) = 0$$

Solve for p

$$p=-18$$

Steps for Solving Linear Equation

Use the distributive property to multiply -\frac{1}{3} by p-3.

$$-\frac{1}{3}p-\frac{1}{3}\left(-3\right)-\frac{1}{4}\left(10-p\right)=0$$

Express -\frac{1}{3}\left(-3\right) as a single fraction.

$$-\frac{1}{3}p+\frac{-\left(-3\right)}{3}-\frac{1}{4}\left(10-p\right)=0$$

Multiply -1 and -3 to get 3.

$$-\frac{1}{3}p+\frac{3}{3}-\frac{1}{4}\left(10-p\right)=0$$

Divide 3 by 3 to get 1.

$$-\frac{1}{3}p+1-\frac{1}{4}\left(10-p\right)=0$$

Use the distributive property to multiply -\frac{1}{4} by 10-p.

$$-\frac{1}{3}p+1-\frac{1}{4}\times 10-\frac{1}{4}\left(-1\right)p=0$$

Express -\frac{1}{4}\times 10 as a single fraction.

$$-\frac{1}{3}p+1+\frac{-10}{4}-\frac{1}{4}\left(-1\right)p=0$$

Reduce the fraction \frac{-10}{4} to lowest terms by extracting and canceling out 2.

$$-\frac{1}{3}p+1-\frac{5}{2}-\frac{1}{4}\left(-1\right)p=0$$

Multiply -\frac{1}{4} and -1 to get \frac{1}{4}.

$$-\frac{1}{3}p+1-\frac{5}{2}+\frac{1}{4}p=0$$

Convert 1 to fraction \frac{2}{2}.

$$-\frac{1}{3}p+\frac{2}{2}-\frac{5}{2}+\frac{1}{4}p=0$$

Since \frac{2}{2} and \frac{5}{2} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{1}{3}p+\frac{2-5}{2}+\frac{1}{4}p=0$$

Subtract 5 from 2 to get -3.

$$-\frac{1}{3}p-\frac{3}{2}+\frac{1}{4}p=0$$

Combine -\frac{1}{3}p and \frac{1}{4}p to get -\frac{1}{12}p.

$$-\frac{1}{12}p-\frac{3}{2}=0$$

Add \frac{3}{2} to both sides. Anything plus zero gives itself.

$$-\frac{1}{12}p=\frac{3}{2}$$

Multiply both sides by -12, the reciprocal of -\frac{1}{12}.

$$p=\frac{3}{2}\left(-12\right)$$

Express \frac{3}{2}\left(-12\right) as a single fraction.

$$p=\frac{3\left(-12\right)}{2}$$

Multiply 3 and -12 to get -36.

$$p=\frac{-36}{2}$$

Divide -36 by 2 to get -18.

$$p=-18$$