Solve -1/3(9x-6y-3)=

$$- \frac { 1 } { 3 } ( 9 x - 6 y - 3 ) =$$

Evaluate

$$1+2y-3x$$

Solution Steps

Use the distributive property to multiply -\frac{1}{3} by 9x-6y-3.

$$-\frac{1}{3}\times 9x-\frac{1}{3}\left(-6\right)y-\frac{1}{3}\left(-3\right)$$

Express -\frac{1}{3}\times 9 as a single fraction.

$$\frac{-9}{3}x-\frac{1}{3}\left(-6\right)y-\frac{1}{3}\left(-3\right)$$

Divide -9 by 3 to get -3.

$$-3x-\frac{1}{3}\left(-6\right)y-\frac{1}{3}\left(-3\right)$$

Express -\frac{1}{3}\left(-6\right) as a single fraction.

$$-3x+\frac{-\left(-6\right)}{3}y-\frac{1}{3}\left(-3\right)$$

Multiply -1 and -6 to get 6.

$$-3x+\frac{6}{3}y-\frac{1}{3}\left(-3\right)$$

Divide 6 by 3 to get 2.

$$-3x+2y-\frac{1}{3}\left(-3\right)$$

Express -\frac{1}{3}\left(-3\right) as a single fraction.

$$-3x+2y+\frac{-\left(-3\right)}{3}$$

Multiply -1 and -3 to get 3.

$$-3x+2y+\frac{3}{3}$$

Divide 3 by 3 to get 1.

$$-3x+2y+1$$

Expand

$$1+2y-3x$$

Solution Steps

Use the distributive property to multiply -\frac{1}{3} by 9x-6y-3.

$$-\frac{1}{3}\times 9x-\frac{1}{3}\left(-6\right)y-\frac{1}{3}\left(-3\right)$$

Express -\frac{1}{3}\times 9 as a single fraction.

$$\frac{-9}{3}x-\frac{1}{3}\left(-6\right)y-\frac{1}{3}\left(-3\right)$$

Divide -9 by 3 to get -3.

$$-3x-\frac{1}{3}\left(-6\right)y-\frac{1}{3}\left(-3\right)$$

Express -\frac{1}{3}\left(-6\right) as a single fraction.

$$-3x+\frac{-\left(-6\right)}{3}y-\frac{1}{3}\left(-3\right)$$

Multiply -1 and -6 to get 6.

$$-3x+\frac{6}{3}y-\frac{1}{3}\left(-3\right)$$

Divide 6 by 3 to get 2.

$$-3x+2y-\frac{1}{3}\left(-3\right)$$

Express -\frac{1}{3}\left(-3\right) as a single fraction.

$$-3x+2y+\frac{-\left(-3\right)}{3}$$

Multiply -1 and -3 to get 3.

$$-3x+2y+\frac{3}{3}$$

Divide 3 by 3 to get 1.

$$-3x+2y+1$$