Solve -1/3*(10-2^2)-15*1/2=

$$- \frac { 1 } { 3 } \cdot ( 10 - 2 ^ { 2 } ) - 15 \cdot \frac { 1 } { 2 } =$$

Evaluate

$$-\frac{19}{2}=-9.5$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$-\frac{1}{3}\left(10-4\right)-15\times \frac{1}{2}$$

Subtract 4 from 10 to get 6.

$$-\frac{1}{3}\times 6-15\times \frac{1}{2}$$

Express -\frac{1}{3}\times 6 as a single fraction.

$$\frac{-6}{3}-15\times \frac{1}{2}$$

Divide -6 by 3 to get -2.

$$-2-15\times \frac{1}{2}$$

Multiply 15 and \frac{1}{2} to get \frac{15}{2}.

$$-2-\frac{15}{2}$$

Convert -2 to fraction -\frac{4}{2}.

$$-\frac{4}{2}-\frac{15}{2}$$

Since -\frac{4}{2} and \frac{15}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-4-15}{2}$$

Subtract 15 from -4 to get -19.

$$-\frac{19}{2}$$

Factor

$$-\frac{19}{2} = -9\frac{1}{2} = -9.5$$