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\frac{-x^{2}+3x+4}{2}
Factor out \frac{1}{2}.
a+b=3 ab=-4=-4
Consider -x^{2}+3x+4. Factor the expression by grouping. First, the expression needs to be rewritten as -x^{2}+ax+bx+4. To find a and b, set up a system to be solved.
-1,4 -2,2
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -4.
-1+4=3 -2+2=0
Calculate the sum for each pair.
a=4 b=-1
The solution is the pair that gives sum 3.
\left(-x^{2}+4x\right)+\left(-x+4\right)
Rewrite -x^{2}+3x+4 as \left(-x^{2}+4x\right)+\left(-x+4\right).
-x\left(x-4\right)-\left(x-4\right)
Factor out -x in the first and -1 in the second group.
\left(x-4\right)\left(-x-1\right)
Factor out common term x-4 by using distributive property.
\frac{\left(x-4\right)\left(-x-1\right)}{2}
Rewrite the complete factored expression.