Solve -1/2^2*0.1+1/2*(-0.2)

$$- \frac { 1 } { 2 ^ { 2 } } \times 0.1 + \frac { 1 } { 2 } \times ( - 0.2 )$$

Evaluate

$$-0.125$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$-\frac{1}{4}\times 0.1+\frac{1}{2}\left(-0.2\right)$$

Convert decimal number 0.1 to fraction \frac{1}{10}.

$$-\frac{1}{4}\times \frac{1}{10}+\frac{1}{2}\left(-0.2\right)$$

Multiply -\frac{1}{4} times \frac{1}{10} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-1}{4\times 10}+\frac{1}{2}\left(-0.2\right)$$

Do the multiplications in the fraction \frac{-1}{4\times 10}.

$$\frac{-1}{40}+\frac{1}{2}\left(-0.2\right)$$

Fraction \frac{-1}{40} can be rewritten as -\frac{1}{40} by extracting the negative sign.

$$-\frac{1}{40}+\frac{1}{2}\left(-0.2\right)$$

Convert decimal number -0.2 to fraction -\frac{2}{10}. Reduce the fraction -\frac{2}{10} to lowest terms by extracting and canceling out 2.

$$-\frac{1}{40}+\frac{1}{2}\left(-\frac{1}{5}\right)$$

Multiply \frac{1}{2} times -\frac{1}{5} by multiplying numerator times numerator and denominator times denominator.

$$-\frac{1}{40}+\frac{1\left(-1\right)}{2\times 5}$$

Do the multiplications in the fraction \frac{1\left(-1\right)}{2\times 5}.

$$-\frac{1}{40}+\frac{-1}{10}$$

Fraction \frac{-1}{10} can be rewritten as -\frac{1}{10} by extracting the negative sign.

$$-\frac{1}{40}-\frac{1}{10}$$

Least common multiple of 40 and 10 is 40. Convert -\frac{1}{40} and \frac{1}{10} to fractions with denominator 40.

$$-\frac{1}{40}-\frac{4}{40}$$

Since -\frac{1}{40} and \frac{4}{40} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-1-4}{40}$$

Subtract 4 from -1 to get -5.

$$\frac{-5}{40}$$

Reduce the fraction \frac{-5}{40} to lowest terms by extracting and canceling out 5.

$$-\frac{1}{8}$$

Factor

$$-0.125$$