Solve -1/1quadx-3/1=x/7+3/1

$$- \frac { 1 } { 1 } \quad \frac { x - 3 } { 1 } = \frac { x } { 7 } + \frac { 3 } { 1 }$$

Solve for x

$$x=0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 7.

$$7\left(-\frac{1}{1}\right)\left(x-3\right)=x+7\times 3$$

Anything divided by one gives itself.

$$7\left(-1\right)\left(x-3\right)=x+7\times 3$$

Multiply 7 and -1 to get -7.

$$-7\left(x-3\right)=x+7\times 3$$

Use the distributive property to multiply -7 by x-3.

$$-7x+21=x+7\times 3$$

Multiply 7 and 3 to get 21.

$$-7x+21=x+21$$

Subtract x from both sides.

$$-7x+21-x=21$$

Combine -7x and -x to get -8x.

$$-8x+21=21$$

Subtract 21 from both sides.

$$-8x=21-21$$

Subtract 21 from 21 to get 0.

$$-8x=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since -8 is not equal to 0, x must be equal to 0.

$$x=0$$