Solve -[-7+(-12)divsqrt[3]{64}]*(-1)^6+(-21+21)^2-sqrt{sqrt{16}}

$$- [ - 7 + ( - 12 ) \div \sqrt[ 3 ] { 64 } ] \cdot ( - 1 ) ^ { 6 } + ( - 21 + 21 ) ^ { 2 } - \sqrt { \sqrt { 16 } }$$

Evaluate

$$8$$

Solution Steps

Calculate \sqrt[3]{64} and get 4.

$$\left(-\left(-7+\frac{-12}{4}\right)\right)\left(-1\right)^{6}+\left(-21+21\right)^{2}-\sqrt{\sqrt{16}}$$

Divide -12 by 4 to get -3.

$$\left(-\left(-7-3\right)\right)\left(-1\right)^{6}+\left(-21+21\right)^{2}-\sqrt{\sqrt{16}}$$

Subtract 3 from -7 to get -10.

$$\left(-\left(-10\right)\right)\left(-1\right)^{6}+\left(-21+21\right)^{2}-\sqrt{\sqrt{16}}$$

The opposite of -10 is 10.

$$10\left(-1\right)^{6}+\left(-21+21\right)^{2}-\sqrt{\sqrt{16}}$$

Calculate -1 to the power of 6 and get 1.

$$10\times 1+\left(-21+21\right)^{2}-\sqrt{\sqrt{16}}$$

Multiply 10 and 1 to get 10.

$$10+\left(-21+21\right)^{2}-\sqrt{\sqrt{16}}$$

Add -21 and 21 to get 0.

$$10+0^{2}-\sqrt{\sqrt{16}}$$

Calculate 0 to the power of 2 and get 0.

$$10+0-\sqrt{\sqrt{16}}$$

Add 10 and 0 to get 10.

$$10-\sqrt{\sqrt{16}}$$

Calculate the square root of 16 and get 4.

$$10-\sqrt{4}$$

Calculate the square root of 4 and get 2.

$$10-2$$

Subtract 2 from 10 to get 8.

$$8$$

Factor

$$2^{3}$$