Solve (y-(-3)=5/4(x-(-1))

$$(y-(-3)= \frac{ 5 }{ 4 } (x-(-1))$$

Solve for x

$$x=\frac{4y+7}{5}$$

Steps for Solving Linear Equation

The opposite of -3 is 3.

$$y+3=\frac{5}{4}\left(x-\left(-1\right)\right)$$

The opposite of -1 is 1.

$$y+3=\frac{5}{4}\left(x+1\right)$$

Use the distributive property to multiply \frac{5}{4} by x+1.

$$y+3=\frac{5}{4}x+\frac{5}{4}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{5}{4}x+\frac{5}{4}=y+3$$

Subtract \frac{5}{4} from both sides.

$$\frac{5}{4}x=y+3-\frac{5}{4}$$

Subtract \frac{5}{4} from 3 to get \frac{7}{4}.

$$\frac{5}{4}x=y+\frac{7}{4}$$

Divide both sides of the equation by \frac{5}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{5}{4}x}{\frac{5}{4}}=\frac{y+\frac{7}{4}}{\frac{5}{4}}$$

Dividing by \frac{5}{4} undoes the multiplication by \frac{5}{4}.

$$x=\frac{y+\frac{7}{4}}{\frac{5}{4}}$$

Divide y+\frac{7}{4} by \frac{5}{4} by multiplying y+\frac{7}{4} by the reciprocal of \frac{5}{4}.

$$x=\frac{4y+7}{5}$$

Solve for y

$$y=\frac{5x-7}{4}$$

Solution Steps

The opposite of -3 is 3.

$$y+3=\frac{5}{4}\left(x-\left(-1\right)\right)$$

The opposite of -1 is 1.

$$y+3=\frac{5}{4}\left(x+1\right)$$

Use the distributive property to multiply \frac{5}{4} by x+1.

$$y+3=\frac{5}{4}x+\frac{5}{4}$$

Subtract 3 from both sides.

$$y=\frac{5}{4}x+\frac{5}{4}-3$$

Subtract 3 from \frac{5}{4} to get -\frac{7}{4}.

$$y=\frac{5}{4}x-\frac{7}{4}$$