Skip to main content
Solve for x
Tick mark Image
Graph

Similar Problems from Web Search

Share

x^{2}-5x=208
Use the distributive property to multiply x-5 by x.
x^{2}-5x-208=0
Subtract 208 from both sides.
x=\frac{-\left(-5\right)±\sqrt{\left(-5\right)^{2}-4\left(-208\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -5 for b, and -208 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-5\right)±\sqrt{25-4\left(-208\right)}}{2}
Square -5.
x=\frac{-\left(-5\right)±\sqrt{25+832}}{2}
Multiply -4 times -208.
x=\frac{-\left(-5\right)±\sqrt{857}}{2}
Add 25 to 832.
x=\frac{5±\sqrt{857}}{2}
The opposite of -5 is 5.
x=\frac{\sqrt{857}+5}{2}
Now solve the equation x=\frac{5±\sqrt{857}}{2} when ± is plus. Add 5 to \sqrt{857}.
x=\frac{5-\sqrt{857}}{2}
Now solve the equation x=\frac{5±\sqrt{857}}{2} when ± is minus. Subtract \sqrt{857} from 5.
x=\frac{\sqrt{857}+5}{2} x=\frac{5-\sqrt{857}}{2}
The equation is now solved.
x^{2}-5x=208
Use the distributive property to multiply x-5 by x.
x^{2}-5x+\left(-\frac{5}{2}\right)^{2}=208+\left(-\frac{5}{2}\right)^{2}
Divide -5, the coefficient of the x term, by 2 to get -\frac{5}{2}. Then add the square of -\frac{5}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-5x+\frac{25}{4}=208+\frac{25}{4}
Square -\frac{5}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}-5x+\frac{25}{4}=\frac{857}{4}
Add 208 to \frac{25}{4}.
\left(x-\frac{5}{2}\right)^{2}=\frac{857}{4}
Factor x^{2}-5x+\frac{25}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{5}{2}\right)^{2}}=\sqrt{\frac{857}{4}}
Take the square root of both sides of the equation.
x-\frac{5}{2}=\frac{\sqrt{857}}{2} x-\frac{5}{2}=-\frac{\sqrt{857}}{2}
Simplify.
x=\frac{\sqrt{857}+5}{2} x=\frac{5-\sqrt{857}}{2}
Add \frac{5}{2} to both sides of the equation.