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x^{2}-x-20=112
Use the distributive property to multiply x-5 by x+4 and combine like terms.
x^{2}-x-20-112=0
Subtract 112 from both sides.
x^{2}-x-132=0
Subtract 112 from -20 to get -132.
x=\frac{-\left(-1\right)±\sqrt{1-4\left(-132\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -1 for b, and -132 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-1\right)±\sqrt{1+528}}{2}
Multiply -4 times -132.
x=\frac{-\left(-1\right)±\sqrt{529}}{2}
Add 1 to 528.
x=\frac{-\left(-1\right)±23}{2}
Take the square root of 529.
x=\frac{1±23}{2}
The opposite of -1 is 1.
x=\frac{24}{2}
Now solve the equation x=\frac{1±23}{2} when ± is plus. Add 1 to 23.
x=12
Divide 24 by 2.
x=-\frac{22}{2}
Now solve the equation x=\frac{1±23}{2} when ± is minus. Subtract 23 from 1.
x=-11
Divide -22 by 2.
x=12 x=-11
The equation is now solved.
x^{2}-x-20=112
Use the distributive property to multiply x-5 by x+4 and combine like terms.
x^{2}-x=112+20
Add 20 to both sides.
x^{2}-x=132
Add 112 and 20 to get 132.
x^{2}-x+\left(-\frac{1}{2}\right)^{2}=132+\left(-\frac{1}{2}\right)^{2}
Divide -1, the coefficient of the x term, by 2 to get -\frac{1}{2}. Then add the square of -\frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-x+\frac{1}{4}=132+\frac{1}{4}
Square -\frac{1}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}-x+\frac{1}{4}=\frac{529}{4}
Add 132 to \frac{1}{4}.
\left(x-\frac{1}{2}\right)^{2}=\frac{529}{4}
Factor x^{2}-x+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{\frac{529}{4}}
Take the square root of both sides of the equation.
x-\frac{1}{2}=\frac{23}{2} x-\frac{1}{2}=-\frac{23}{2}
Simplify.
x=12 x=-11
Add \frac{1}{2} to both sides of the equation.