Solve (x-45)*98-015*10*98=(10+45+x)*22

$$(x-45) \times 98-015 \times 10 \times 98=(10+45+x) \times 22$$

Solve for x

$$x = \frac{1405}{19} = 73\frac{18}{19} \approx 73.947368421$$

Steps for Solving Linear Equation

Use the distributive property to multiply x-45 by 98.

$$98x-4410-0\times 15\times 10\times 98=\left(10+45+x\right)\times 22$$

Multiply 0 and 15 to get 0.

$$98x-4410-0\times 10\times 98=\left(10+45+x\right)\times 22$$

Multiply 0 and 10 to get 0.

$$98x-4410-0\times 98=\left(10+45+x\right)\times 22$$

Multiply 0 and 98 to get 0.

$$98x-4410-0=\left(10+45+x\right)\times 22$$

Add 10 and 45 to get 55.

$$98x-4410-0=\left(55+x\right)\times 22$$

Use the distributive property to multiply 55+x by 22.

$$98x-4410-0=1210+22x$$

Subtract 22x from both sides.

$$98x-4410-0-22x=1210$$

Reorder the terms.

$$-22x+98x-4410=1210$$

Combine -22x and 98x to get 76x.

$$76x-4410=1210$$

Add 4410 to both sides.

$$76x=1210+4410$$

Add 1210 and 4410 to get 5620.

$$76x=5620$$

Divide both sides by 76.

$$x=\frac{5620}{76}$$

Reduce the fraction \frac{5620}{76} to lowest terms by extracting and canceling out 4.

$$x=\frac{1405}{19}$$