Solve (x-20)+(x-40)+(x/2-10)=180

$$(x-20)+(x-40)+( \frac{ x }{ 2 } -10) = 180$$

Solve for x

$$x=100$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$2x-40+2x-80+x-20=360$$

Combine 2x and 2x to get 4x.

$$4x-40-80+x-20=360$$

Subtract 80 from -40 to get -120.

$$4x-120+x-20=360$$

Combine 4x and x to get 5x.

$$5x-120-20=360$$

Subtract 20 from -120 to get -140.

$$5x-140=360$$

Add 140 to both sides.

$$5x=360+140$$

Add 360 and 140 to get 500.

$$5x=500$$

Divide both sides by 5.

$$x=\frac{500}{5}$$

Divide 500 by 5 to get 100.

$$x=100$$