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x^{2}+9x=19
Use the distributive property to multiply x by x+9.
x^{2}+9x-19=0
Subtract 19 from both sides.
x=\frac{-9±\sqrt{9^{2}-4\left(-19\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 9 for b, and -19 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-9±\sqrt{81-4\left(-19\right)}}{2}
Square 9.
x=\frac{-9±\sqrt{81+76}}{2}
Multiply -4 times -19.
x=\frac{-9±\sqrt{157}}{2}
Add 81 to 76.
x=\frac{\sqrt{157}-9}{2}
Now solve the equation x=\frac{-9±\sqrt{157}}{2} when ± is plus. Add -9 to \sqrt{157}.
x=\frac{-\sqrt{157}-9}{2}
Now solve the equation x=\frac{-9±\sqrt{157}}{2} when ± is minus. Subtract \sqrt{157} from -9.
x=\frac{\sqrt{157}-9}{2} x=\frac{-\sqrt{157}-9}{2}
The equation is now solved.
x^{2}+9x=19
Use the distributive property to multiply x by x+9.
x^{2}+9x+\left(\frac{9}{2}\right)^{2}=19+\left(\frac{9}{2}\right)^{2}
Divide 9, the coefficient of the x term, by 2 to get \frac{9}{2}. Then add the square of \frac{9}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+9x+\frac{81}{4}=19+\frac{81}{4}
Square \frac{9}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}+9x+\frac{81}{4}=\frac{157}{4}
Add 19 to \frac{81}{4}.
\left(x+\frac{9}{2}\right)^{2}=\frac{157}{4}
Factor x^{2}+9x+\frac{81}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{9}{2}\right)^{2}}=\sqrt{\frac{157}{4}}
Take the square root of both sides of the equation.
x+\frac{9}{2}=\frac{\sqrt{157}}{2} x+\frac{9}{2}=-\frac{\sqrt{157}}{2}
Simplify.
x=\frac{\sqrt{157}-9}{2} x=\frac{-\sqrt{157}-9}{2}
Subtract \frac{9}{2} from both sides of the equation.