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x^{2}+9x+8=-12
Use the distributive property to multiply x+8 by x+1 and combine like terms.
x^{2}+9x+8+12=0
Add 12 to both sides.
x^{2}+9x+20=0
Add 8 and 12 to get 20.
x=\frac{-9±\sqrt{9^{2}-4\times 20}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 9 for b, and 20 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-9±\sqrt{81-4\times 20}}{2}
Square 9.
x=\frac{-9±\sqrt{81-80}}{2}
Multiply -4 times 20.
x=\frac{-9±\sqrt{1}}{2}
Add 81 to -80.
x=\frac{-9±1}{2}
Take the square root of 1.
x=-\frac{8}{2}
Now solve the equation x=\frac{-9±1}{2} when ± is plus. Add -9 to 1.
x=-4
Divide -8 by 2.
x=-\frac{10}{2}
Now solve the equation x=\frac{-9±1}{2} when ± is minus. Subtract 1 from -9.
x=-5
Divide -10 by 2.
x=-4 x=-5
The equation is now solved.
x^{2}+9x+8=-12
Use the distributive property to multiply x+8 by x+1 and combine like terms.
x^{2}+9x=-12-8
Subtract 8 from both sides.
x^{2}+9x=-20
Subtract 8 from -12 to get -20.
x^{2}+9x+\left(\frac{9}{2}\right)^{2}=-20+\left(\frac{9}{2}\right)^{2}
Divide 9, the coefficient of the x term, by 2 to get \frac{9}{2}. Then add the square of \frac{9}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+9x+\frac{81}{4}=-20+\frac{81}{4}
Square \frac{9}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}+9x+\frac{81}{4}=\frac{1}{4}
Add -20 to \frac{81}{4}.
\left(x+\frac{9}{2}\right)^{2}=\frac{1}{4}
Factor x^{2}+9x+\frac{81}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{9}{2}\right)^{2}}=\sqrt{\frac{1}{4}}
Take the square root of both sides of the equation.
x+\frac{9}{2}=\frac{1}{2} x+\frac{9}{2}=-\frac{1}{2}
Simplify.
x=-4 x=-5
Subtract \frac{9}{2} from both sides of the equation.