Solve (x+4)(16-4x+x^2)-x(x^2+8)=-192

$$(x+4)(16-4x+ { x }^{ 2 } )-x( { x }^{ 2 } +8)=-192$$

Solve for x

$$x=32$$

Steps for Solving Linear Equation

Use the distributive property to multiply x+4 by 16-4x+x^{2} and combine like terms.

$$x^{3}+64-x\left(x^{2}+8\right)=-192$$

Use the distributive property to multiply x by x^{2}+8.

$$x^{3}+64-\left(x^{3}+8x\right)=-192$$

To find the opposite of x^{3}+8x, find the opposite of each term.

$$x^{3}+64-x^{3}-8x=-192$$

Combine x^{3} and -x^{3} to get 0.

$$64-8x=-192$$

Subtract 64 from both sides.

$$-8x=-192-64$$

Subtract 64 from -192 to get -256.

$$-8x=-256$$

Divide both sides by -8.

$$x=\frac{-256}{-8}$$

Divide -256 by -8 to get 32.

$$x=32$$