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Solve for x (complex solution)
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x^{2}+5x+6=x-2
Use the distributive property to multiply x+2 by x+3 and combine like terms.
x^{2}+5x+6-x=-2
Subtract x from both sides.
x^{2}+4x+6=-2
Combine 5x and -x to get 4x.
x^{2}+4x+6+2=0
Add 2 to both sides.
x^{2}+4x+8=0
Add 6 and 2 to get 8.
x=\frac{-4±\sqrt{4^{2}-4\times 8}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 4 for b, and 8 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-4±\sqrt{16-4\times 8}}{2}
Square 4.
x=\frac{-4±\sqrt{16-32}}{2}
Multiply -4 times 8.
x=\frac{-4±\sqrt{-16}}{2}
Add 16 to -32.
x=\frac{-4±4i}{2}
Take the square root of -16.
x=\frac{-4+4i}{2}
Now solve the equation x=\frac{-4±4i}{2} when ± is plus. Add -4 to 4i.
x=-2+2i
Divide -4+4i by 2.
x=\frac{-4-4i}{2}
Now solve the equation x=\frac{-4±4i}{2} when ± is minus. Subtract 4i from -4.
x=-2-2i
Divide -4-4i by 2.
x=-2+2i x=-2-2i
The equation is now solved.
x^{2}+5x+6=x-2
Use the distributive property to multiply x+2 by x+3 and combine like terms.
x^{2}+5x+6-x=-2
Subtract x from both sides.
x^{2}+4x+6=-2
Combine 5x and -x to get 4x.
x^{2}+4x=-2-6
Subtract 6 from both sides.
x^{2}+4x=-8
Subtract 6 from -2 to get -8.
x^{2}+4x+2^{2}=-8+2^{2}
Divide 4, the coefficient of the x term, by 2 to get 2. Then add the square of 2 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+4x+4=-8+4
Square 2.
x^{2}+4x+4=-4
Add -8 to 4.
\left(x+2\right)^{2}=-4
Factor x^{2}+4x+4. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+2\right)^{2}}=\sqrt{-4}
Take the square root of both sides of the equation.
x+2=2i x+2=-2i
Simplify.
x=-2+2i x=-2-2i
Subtract 2 from both sides of the equation.