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x^{2}-x-2=3
Use the distributive property to multiply x+1 by x-2 and combine like terms.
x^{2}-x-2-3=0
Subtract 3 from both sides.
x^{2}-x-5=0
Subtract 3 from -2 to get -5.
x=\frac{-\left(-1\right)±\sqrt{1-4\left(-5\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -1 for b, and -5 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-1\right)±\sqrt{1+20}}{2}
Multiply -4 times -5.
x=\frac{-\left(-1\right)±\sqrt{21}}{2}
Add 1 to 20.
x=\frac{1±\sqrt{21}}{2}
The opposite of -1 is 1.
x=\frac{\sqrt{21}+1}{2}
Now solve the equation x=\frac{1±\sqrt{21}}{2} when ± is plus. Add 1 to \sqrt{21}.
x=\frac{1-\sqrt{21}}{2}
Now solve the equation x=\frac{1±\sqrt{21}}{2} when ± is minus. Subtract \sqrt{21} from 1.
x=\frac{\sqrt{21}+1}{2} x=\frac{1-\sqrt{21}}{2}
The equation is now solved.
x^{2}-x-2=3
Use the distributive property to multiply x+1 by x-2 and combine like terms.
x^{2}-x=3+2
Add 2 to both sides.
x^{2}-x=5
Add 3 and 2 to get 5.
x^{2}-x+\left(-\frac{1}{2}\right)^{2}=5+\left(-\frac{1}{2}\right)^{2}
Divide -1, the coefficient of the x term, by 2 to get -\frac{1}{2}. Then add the square of -\frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-x+\frac{1}{4}=5+\frac{1}{4}
Square -\frac{1}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}-x+\frac{1}{4}=\frac{21}{4}
Add 5 to \frac{1}{4}.
\left(x-\frac{1}{2}\right)^{2}=\frac{21}{4}
Factor x^{2}-x+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{\frac{21}{4}}
Take the square root of both sides of the equation.
x-\frac{1}{2}=\frac{\sqrt{21}}{2} x-\frac{1}{2}=-\frac{\sqrt{21}}{2}
Simplify.
x=\frac{\sqrt{21}+1}{2} x=\frac{1-\sqrt{21}}{2}
Add \frac{1}{2} to both sides of the equation.