Solve (x+1)(x-1)(x-8)

$$(x+1)(x-1)(x-8)$$

Evaluate

$$\left(x-8\right)\left(x^{2}-1\right)$$

Solution Steps

Apply the distributive property by multiplying each term of x+1 by each term of x-1.

$$\left(x^{2}-x+x-1\right)\left(x-8\right)$$

Combine -x and x to get 0.

$$\left(x^{2}-1\right)\left(x-8\right)$$

Apply the distributive property by multiplying each term of x^{2}-1 by each term of x-8.

$$x^{3}-8x^{2}-x+8$$

Expand

$$x^{3}-8x^{2}-x+8$$

Solution Steps

Apply the distributive property by multiplying each term of x+1 by each term of x-1.

$$\left(x^{2}-x+x-1\right)\left(x-8\right)$$

Combine -x and x to get 0.

$$\left(x^{2}-1\right)\left(x-8\right)$$

Apply the distributive property by multiplying each term of x^{2}-1 by each term of x-8.

$$x^{3}-8x^{2}-x+8$$