Solve (x+4/3)(x-1/3)

$$(x+ \frac{ 4 }{ 3 } )(x- \frac{ 1 }{ 3 } )$$

Evaluate

$$x^{2}+x-\frac{4}{9}$$

Solution Steps

Apply the distributive property by multiplying each term of x+\frac{4}{3} by each term of x-\frac{1}{3}.

$$x^{2}+x\left(-\frac{1}{3}\right)+\frac{4}{3}x+\frac{4}{3}\left(-\frac{1}{3}\right)$$

Combine x\left(-\frac{1}{3}\right) and \frac{4}{3}x to get x.

$$x^{2}+x+\frac{4}{3}\left(-\frac{1}{3}\right)$$

Multiply \frac{4}{3} times -\frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$x^{2}+x+\frac{4\left(-1\right)}{3\times 3}$$

Do the multiplications in the fraction \frac{4\left(-1\right)}{3\times 3}.

$$x^{2}+x+\frac{-4}{9}$$

Fraction \frac{-4}{9} can be rewritten as -\frac{4}{9} by extracting the negative sign.

$$x^{2}+x-\frac{4}{9}$$

Expand

$$x^{2}+x-\frac{4}{9}$$

Solution Steps

Apply the distributive property by multiplying each term of x+\frac{4}{3} by each term of x-\frac{1}{3}.

$$x^{2}+x\left(-\frac{1}{3}\right)+\frac{4}{3}x+\frac{4}{3}\left(-\frac{1}{3}\right)$$

Combine x\left(-\frac{1}{3}\right) and \frac{4}{3}x to get x.

$$x^{2}+x+\frac{4}{3}\left(-\frac{1}{3}\right)$$

Multiply \frac{4}{3} times -\frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$x^{2}+x+\frac{4\left(-1\right)}{3\times 3}$$

Do the multiplications in the fraction \frac{4\left(-1\right)}{3\times 3}.

$$x^{2}+x+\frac{-4}{9}$$

Fraction \frac{-4}{9} can be rewritten as -\frac{4}{9} by extracting the negative sign.

$$x^{2}+x-\frac{4}{9}$$