Solve (9998%*1)+(2*02%)+(3*00%)

$$(9998 \% \times 1)+(2 \times 02 \% )+(3 \times 00 \% )$$

Evaluate

$$\frac{4999}{50}=99.98$$

Solution Steps

Multiply 2 and 0 to get 0. Multiply 3 and 0 to get 0.

$$\frac{9998}{100}\times 1+0\times \frac{2}{100}+0\times \frac{0}{100}$$

Reduce the fraction \frac{9998}{100} to lowest terms by extracting and canceling out 2.

$$\frac{4999}{50}\times 1+0\times \frac{2}{100}+0\times \frac{0}{100}$$

Multiply \frac{4999}{50} and 1 to get \frac{4999}{50}.

$$\frac{4999}{50}+0\times \frac{2}{100}+0\times \frac{0}{100}$$

Reduce the fraction \frac{2}{100} to lowest terms by extracting and canceling out 2.

$$\frac{4999}{50}+0\times \frac{1}{50}+0\times \frac{0}{100}$$

Multiply 0 and \frac{1}{50} to get 0.

$$\frac{4999}{50}+0+0\times \frac{0}{100}$$

Add \frac{4999}{50} and 0 to get \frac{4999}{50}.

$$\frac{4999}{50}+0\times \frac{0}{100}$$

Zero divided by any non-zero number gives zero.

$$\frac{4999}{50}+0\times 0$$

Multiply 0 and 0 to get 0.

$$\frac{4999}{50}+0$$

Add \frac{4999}{50} and 0 to get \frac{4999}{50}.

$$\frac{4999}{50}$$

Factor

$$\frac{4999}{2 \cdot 5 ^ {2}} = 99\frac{49}{50} = 99.98$$