Solve (8x)(5x)=6760

$$(8x)(5x)=6760$$

Solve for x

$$x=13$$

$$x=-13$$

Steps by Finding Square Root

Multiply x and x to get x^{2}.

$$8x^{2}\times 5=6760$$

Multiply 8 and 5 to get 40.

$$40x^{2}=6760$$

Divide both sides by 40.

$$x^{2}=\frac{6760}{40}$$

Divide 6760 by 40 to get 169.

$$x^{2}=169$$

Take the square root of both sides of the equation.

$$x=13 x=-13$$

Steps Using the Quadratic Formula

Multiply x and x to get x^{2}.

$$8x^{2}\times 5=6760$$

Multiply 8 and 5 to get 40.

$$40x^{2}=6760$$

Subtract 6760 from both sides.

$$40x^{2}-6760=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 40 for a, 0 for b, and -6760 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 40\left(-6760\right)}}{2\times 40}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 40\left(-6760\right)}}{2\times 40}$$

Multiply -4 times 40.

$$x=\frac{0±\sqrt{-160\left(-6760\right)}}{2\times 40}$$

Multiply -160 times -6760.

$$x=\frac{0±\sqrt{1081600}}{2\times 40}$$

Take the square root of 1081600.

$$x=\frac{0±1040}{2\times 40}$$

Multiply 2 times 40.

$$x=\frac{0±1040}{80}$$

Now solve the equation x=\frac{0±1040}{80} when ± is plus. Divide 1040 by 80.

$$x=13$$

Now solve the equation x=\frac{0±1040}{80} when ± is minus. Divide -1040 by 80.

$$x=-13$$

The equation is now solved.

$$x=13 x=-13$$