Solve (8*4-35/6)+(51/3-2*4)

$$(8 \cdot 4-3 \frac{ 5 }{ 6 } )+(5 \frac{ 1 }{ 3 } -2 \cdot 4)$$

Evaluate

$$\frac{51}{2}=25.5$$

Solution Steps

Multiply 8 and 4 to get 32.

$$32-\frac{3\times 6+5}{6}+\frac{5\times 3+1}{3}-2\times 4$$

Multiply 3 and 6 to get 18.

$$32-\frac{18+5}{6}+\frac{5\times 3+1}{3}-2\times 4$$

Add 18 and 5 to get 23.

$$32-\frac{23}{6}+\frac{5\times 3+1}{3}-2\times 4$$

Convert 32 to fraction \frac{192}{6}.

$$\frac{192}{6}-\frac{23}{6}+\frac{5\times 3+1}{3}-2\times 4$$

Since \frac{192}{6} and \frac{23}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{192-23}{6}+\frac{5\times 3+1}{3}-2\times 4$$

Subtract 23 from 192 to get 169.

$$\frac{169}{6}+\frac{5\times 3+1}{3}-2\times 4$$

Multiply 5 and 3 to get 15.

$$\frac{169}{6}+\frac{15+1}{3}-2\times 4$$

Add 15 and 1 to get 16.

$$\frac{169}{6}+\frac{16}{3}-2\times 4$$

Multiply 2 and 4 to get 8.

$$\frac{169}{6}+\frac{16}{3}-8$$

Convert 8 to fraction \frac{24}{3}.

$$\frac{169}{6}+\frac{16}{3}-\frac{24}{3}$$

Since \frac{16}{3} and \frac{24}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{169}{6}+\frac{16-24}{3}$$

Subtract 24 from 16 to get -8.

$$\frac{169}{6}-\frac{8}{3}$$

Least common multiple of 6 and 3 is 6. Convert \frac{169}{6} and \frac{8}{3} to fractions with denominator 6.

$$\frac{169}{6}-\frac{16}{6}$$

Since \frac{169}{6} and \frac{16}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{169-16}{6}$$

Subtract 16 from 169 to get 153.

$$\frac{153}{6}$$

Reduce the fraction \frac{153}{6} to lowest terms by extracting and canceling out 3.

$$\frac{51}{2}$$

Factor

$$\frac{3 \cdot 17}{2} = 25\frac{1}{2} = 25.5$$