Solve (8!div(2!6!))*04^2*left(1-04right)^6

$$(8 ! \div (2 ! 6 ! )) \times { 04 }^{ 2 } \times { \left(1-04 \right) }^{ 6 }$$

Evaluate

$$0$$

Solution Steps

The factorial of 8 is 40320.

$$\frac{40320}{2!\times 6!}\times \left(0\times 4\right)^{2}\left(1-0\times 4\right)^{6}$$

The factorial of 2 is 2.

$$\frac{40320}{2\times 6!}\times \left(0\times 4\right)^{2}\left(1-0\times 4\right)^{6}$$

The factorial of 6 is 720.

$$\frac{40320}{2\times 720}\times \left(0\times 4\right)^{2}\left(1-0\times 4\right)^{6}$$

Multiply 2 and 720 to get 1440.

$$\frac{40320}{1440}\times \left(0\times 4\right)^{2}\left(1-0\times 4\right)^{6}$$

Divide 40320 by 1440 to get 28.

$$28\times \left(0\times 4\right)^{2}\left(1-0\times 4\right)^{6}$$

Multiply 0 and 4 to get 0.

$$28\times 0^{2}\left(1-0\times 4\right)^{6}$$

Calculate 0 to the power of 2 and get 0.

$$28\times 0\left(1-0\times 4\right)^{6}$$

Multiply 28 and 0 to get 0.

$$0\left(1-0\times 4\right)^{6}$$

Multiply 0 and 4 to get 0.

$$0\left(1-0\right)^{6}$$

Subtract 0 from 1 to get 1.

$$0\times 1^{6}$$

Calculate 1 to the power of 6 and get 1.

$$0\times 1$$

Multiply 0 and 1 to get 0.

$$0$$

Factor

$$0$$