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720x^{2}=2592
Multiply x and x to get x^{2}.
x^{2}=\frac{2592}{720}
Divide both sides by 720.
x^{2}=\frac{18}{5}
Reduce the fraction \frac{2592}{720} to lowest terms by extracting and canceling out 144.
x=\frac{3\sqrt{10}}{5} x=-\frac{3\sqrt{10}}{5}
Take the square root of both sides of the equation.
720x^{2}=2592
Multiply x and x to get x^{2}.
720x^{2}-2592=0
Subtract 2592 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times 720\left(-2592\right)}}{2\times 720}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 720 for a, 0 for b, and -2592 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 720\left(-2592\right)}}{2\times 720}
Square 0.
x=\frac{0±\sqrt{-2880\left(-2592\right)}}{2\times 720}
Multiply -4 times 720.
x=\frac{0±\sqrt{7464960}}{2\times 720}
Multiply -2880 times -2592.
x=\frac{0±864\sqrt{10}}{2\times 720}
Take the square root of 7464960.
x=\frac{0±864\sqrt{10}}{1440}
Multiply 2 times 720.
x=\frac{3\sqrt{10}}{5}
Now solve the equation x=\frac{0±864\sqrt{10}}{1440} when ± is plus.
x=-\frac{3\sqrt{10}}{5}
Now solve the equation x=\frac{0±864\sqrt{10}}{1440} when ± is minus.
x=\frac{3\sqrt{10}}{5} x=-\frac{3\sqrt{10}}{5}
The equation is now solved.