Solve (70+72+74+76+78+80+82+84+86+88+90+92)div12=

$$(70+72+74+76+78+80+82+84+86+88+90+92) \div 12=$$

Evaluate

$$81$$

Solution Steps

Add 70 and 72 to get 142.

$$\frac{142+74+76+78+80+82+84+86+88+90+92}{12}$$

Add 142 and 74 to get 216.

$$\frac{216+76+78+80+82+84+86+88+90+92}{12}$$

Add 216 and 76 to get 292.

$$\frac{292+78+80+82+84+86+88+90+92}{12}$$

Add 292 and 78 to get 370.

$$\frac{370+80+82+84+86+88+90+92}{12}$$

Add 370 and 80 to get 450.

$$\frac{450+82+84+86+88+90+92}{12}$$

Add 450 and 82 to get 532.

$$\frac{532+84+86+88+90+92}{12}$$

Add 532 and 84 to get 616.

$$\frac{616+86+88+90+92}{12}$$

Add 616 and 86 to get 702.

$$\frac{702+88+90+92}{12}$$

Add 702 and 88 to get 790.

$$\frac{790+90+92}{12}$$

Add 790 and 90 to get 880.

$$\frac{880+92}{12}$$

Add 880 and 92 to get 972.

$$\frac{972}{12}$$

Divide 972 by 12 to get 81.

$$81$$

Factor

$$3^{4}$$