Solve (7-5)4+3(4-2)+(8-2)5-2(11-10)

$$(7-5)4+3(4-2)+(8-2)5-2(11-10)$$

Evaluate

$$42$$

Solution Steps

Subtract 5 from 7 to get 2.

$$2\times 4+3\left(4-2\right)+\left(8-2\right)\times 5-2\left(11-10\right)$$

Multiply 2 and 4 to get 8.

$$8+3\left(4-2\right)+\left(8-2\right)\times 5-2\left(11-10\right)$$

Subtract 2 from 4 to get 2.

$$8+3\times 2+\left(8-2\right)\times 5-2\left(11-10\right)$$

Multiply 3 and 2 to get 6.

$$8+6+\left(8-2\right)\times 5-2\left(11-10\right)$$

Add 8 and 6 to get 14.

$$14+\left(8-2\right)\times 5-2\left(11-10\right)$$

Subtract 2 from 8 to get 6.

$$14+6\times 5-2\left(11-10\right)$$

Multiply 6 and 5 to get 30.

$$14+30-2\left(11-10\right)$$

Add 14 and 30 to get 44.

$$44-2\left(11-10\right)$$

Subtract 10 from 11 to get 1.

$$44-2\times 1$$

Multiply 2 and 1 to get 2.

$$44-2$$

Subtract 2 from 44 to get 42.

$$42$$

Factor

$$2\times 3\times 7$$