Solve (7-2)*(3-8)+23div2+1

$$(7-2) \times (3-8)+23 \div 2+1$$

Evaluate

$$-\frac{25}{2}=-12.5$$

Solution Steps

Subtract 2 from 7 to get 5.

$$5\left(3-8\right)+\frac{23}{2}+1$$

Subtract 8 from 3 to get -5.

$$5\left(-5\right)+\frac{23}{2}+1$$

Multiply 5 and -5 to get -25.

$$-25+\frac{23}{2}+1$$

Convert -25 to fraction -\frac{50}{2}.

$$-\frac{50}{2}+\frac{23}{2}+1$$

Since -\frac{50}{2} and \frac{23}{2} have the same denominator, add them by adding their numerators.

$$\frac{-50+23}{2}+1$$

Add -50 and 23 to get -27.

$$-\frac{27}{2}+1$$

Convert 1 to fraction \frac{2}{2}.

$$-\frac{27}{2}+\frac{2}{2}$$

Since -\frac{27}{2} and \frac{2}{2} have the same denominator, add them by adding their numerators.

$$\frac{-27+2}{2}$$

Add -27 and 2 to get -25.

$$-\frac{25}{2}$$

Factor

$$-\frac{25}{2} = -12\frac{1}{2} = -12.5$$