Solve (6x-2)(x+05)div6-(x+1)(x+05)=1

$$(6x-2)(x+05) \div 6-(x+1)(x+05)=1$$

Solve for x

$$x=-\frac{3}{4}=-0.75$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6.

$$\left(6x-2\right)\left(x+0\times 5\right)-6\left(x+1\right)\left(x+0\times 5\right)=6$$

Multiply 0 and 5 to get 0.

$$\left(6x-2\right)\left(x+0\right)-6\left(x+1\right)\left(x+0\times 5\right)=6$$

Anything plus zero gives itself.

$$\left(6x-2\right)x-6\left(x+1\right)\left(x+0\times 5\right)=6$$

Use the distributive property to multiply 6x-2 by x.

$$6x^{2}-2x-6\left(x+1\right)\left(x+0\times 5\right)=6$$

Multiply 0 and 5 to get 0.

$$6x^{2}-2x-6\left(x+1\right)\left(x+0\right)=6$$

Anything plus zero gives itself.

$$6x^{2}-2x-6\left(x+1\right)x=6$$

Use the distributive property to multiply -6 by x+1.

$$6x^{2}-2x+\left(-6x-6\right)x=6$$

Use the distributive property to multiply -6x-6 by x.

$$6x^{2}-2x-6x^{2}-6x=6$$

Combine 6x^{2} and -6x^{2} to get 0.

$$-2x-6x=6$$

Combine -2x and -6x to get -8x.

$$-8x=6$$

Divide both sides by -8.

$$x=\frac{6}{-8}$$

Reduce the fraction \frac{6}{-8} to lowest terms by extracting and canceling out 2.

$$x=-\frac{3}{4}$$