Solve (641/3)1/2+4^2

$$(64 \frac{ 1 }{ 3 } ) \frac{ 1 }{ 2 } + { 4 }^{ 2 }$$

Evaluate

$$\frac{289}{6}\approx 48.166666667$$

Solution Steps

Multiply 64 and 3 to get 192.

$$\frac{192+1}{3}\times \frac{1}{2}+4^{2}$$

Add 192 and 1 to get 193.

$$\frac{193}{3}\times \frac{1}{2}+4^{2}$$

Multiply \frac{193}{3} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{193\times 1}{3\times 2}+4^{2}$$

Do the multiplications in the fraction \frac{193\times 1}{3\times 2}.

$$\frac{193}{6}+4^{2}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{193}{6}+16$$

Convert 16 to fraction \frac{96}{6}.

$$\frac{193}{6}+\frac{96}{6}$$

Since \frac{193}{6} and \frac{96}{6} have the same denominator, add them by adding their numerators.

$$\frac{193+96}{6}$$

Add 193 and 96 to get 289.

$$\frac{289}{6}$$

Factor

$$\frac{17 ^ {2}}{2 \cdot 3} = 48\frac{1}{6} = 48.166666666666664$$