Solve (6-3/5)(6+3/5)=

$$(6- \frac{ 3 }{ 5 } )(6+ \frac{ 3 }{ 5 } )=$$

Evaluate

$$\frac{891}{25}=35.64$$

Solution Steps

Convert 6 to fraction \frac{30}{5}.

$$\left(\frac{30}{5}-\frac{3}{5}\right)\left(6+\frac{3}{5}\right)$$

Since \frac{30}{5} and \frac{3}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{30-3}{5}\left(6+\frac{3}{5}\right)$$

Subtract 3 from 30 to get 27.

$$\frac{27}{5}\left(6+\frac{3}{5}\right)$$

Convert 6 to fraction \frac{30}{5}.

$$\frac{27}{5}\left(\frac{30}{5}+\frac{3}{5}\right)$$

Since \frac{30}{5} and \frac{3}{5} have the same denominator, add them by adding their numerators.

$$\frac{27}{5}\times \frac{30+3}{5}$$

Add 30 and 3 to get 33.

$$\frac{27}{5}\times \frac{33}{5}$$

Multiply \frac{27}{5} times \frac{33}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{27\times 33}{5\times 5}$$

Do the multiplications in the fraction \frac{27\times 33}{5\times 5}.

$$\frac{891}{25}$$

Factor

$$\frac{3 ^ {4} \cdot 11}{5 ^ {2}} = 35\frac{16}{25} = 35.64$$