Solve (6+42+12+30)-(-30-6-42-12)

$$(6+42+12+30)-(-30-6-42-12)$$

Evaluate

$$180$$

Solution Steps

Add 6 and 42 to get 48.

$$48+12+30-\left(-30-6-42-12\right)$$

Add 48 and 12 to get 60.

$$60+30-\left(-30-6-42-12\right)$$

Add 60 and 30 to get 90.

$$90-\left(-30-6-42-12\right)$$

Subtract 6 from -30 to get -36.

$$90-\left(-36-42-12\right)$$

Subtract 42 from -36 to get -78.

$$90-\left(-78-12\right)$$

Subtract 12 from -78 to get -90.

$$90-\left(-90\right)$$

The opposite of -90 is 90.

$$90+90$$

Add 90 and 90 to get 180.

$$180$$

Factor

$$2^{2}\times 3^{2}\times 5$$