Solve (5x+4)*(x+2)-(5x-1)*(x+3)

$$(5x+4) \times (x+2)-(5x-1) \times (x+3)$$

Evaluate

$$11$$

Solution Steps

Apply the distributive property by multiplying each term of 5x+4 by each term of x+2.

$$5x^{2}+10x+4x+8-\left(5x-1\right)\left(x+3\right)$$

Combine 10x and 4x to get 14x.

$$5x^{2}+14x+8-\left(5x-1\right)\left(x+3\right)$$

Apply the distributive property by multiplying each term of 5x-1 by each term of x+3.

$$5x^{2}+14x+8-\left(5x^{2}+15x-x-3\right)$$

Combine 15x and -x to get 14x.

$$5x^{2}+14x+8-\left(5x^{2}+14x-3\right)$$

To find the opposite of 5x^{2}+14x-3, find the opposite of each term.

$$5x^{2}+14x+8-5x^{2}-14x-\left(-3\right)$$

The opposite of -3 is 3.

$$5x^{2}+14x+8-5x^{2}-14x+3$$

Combine 5x^{2} and -5x^{2} to get 0.

$$14x+8-14x+3$$

Combine 14x and -14x to get 0.

$$8+3$$

Add 8 and 3 to get 11.

$$11$$

Factor

$$11$$