Solve (5(4^2)*(0.5*4)2)%+12

$$(5( { 4 }^{ 2 } ) \times (0.5 \times 4)2) \% +12$$

Evaluate

$$15.2$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$\frac{5\times 4^{3}\times 0.5\times 2}{100}+12$$

Calculate 4 to the power of 3 and get 64.

$$\frac{5\times 64\times 0.5\times 2}{100}+12$$

Multiply 5 and 64 to get 320.

$$\frac{320\times 0.5\times 2}{100}+12$$

Multiply 320 and 0.5 to get 160.

$$\frac{160\times 2}{100}+12$$

Multiply 160 and 2 to get 320.

$$\frac{320}{100}+12$$

Reduce the fraction \frac{320}{100} to lowest terms by extracting and canceling out 20.

$$\frac{16}{5}+12$$

Convert 12 to fraction \frac{60}{5}.

$$\frac{16}{5}+\frac{60}{5}$$

Since \frac{16}{5} and \frac{60}{5} have the same denominator, add them by adding their numerators.

$$\frac{16+60}{5}$$

Add 16 and 60 to get 76.

$$\frac{76}{5}$$

Factor

$$\frac{19 \cdot 2 ^ {2}}{5} = 15\frac{1}{5} = 15.2$$