Solve (5*6div3+1)+(48div4*2-3*1)+5*2)-3=

$$(5 \times 6 \div 3+1)+(48 \div 4 \times 2-3 \times 1)+5 \times 2)-3=$$

Evaluate

$$42$$

Solution Steps

Multiply 5 and 6 to get 30.

$$\frac{30}{3}+1+\frac{48}{4}\times 2-3\times 1+5\times 2$$

Divide 30 by 3 to get 10.

$$10+1+\frac{48}{4}\times 2-3\times 1+5\times 2$$

Add 10 and 1 to get 11.

$$11+\frac{48}{4}\times 2-3\times 1+5\times 2$$

Divide 48 by 4 to get 12.

$$11+12\times 2-3\times 1+5\times 2$$

Multiply 12 and 2 to get 24.

$$11+24-3\times 1+5\times 2$$

Multiply 3 and 1 to get 3.

$$11+24-3+5\times 2$$

Subtract 3 from 24 to get 21.

$$11+21+5\times 2$$

Add 11 and 21 to get 32.

$$32+5\times 2$$

Multiply 5 and 2 to get 10.

$$32+10$$

Add 32 and 10 to get 42.

$$42$$

Factor

$$2\times 3\times 7$$