Solve (48-x)(10+x/3)

$$(48-x)(10+ \frac{ x }{ 3 } )$$

Evaluate

$$\frac{\left(48-x\right)\left(x+30\right)}{3}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 10 times \frac{3}{3}.

$$\left(48-x\right)\left(\frac{10\times 3}{3}+\frac{x}{3}\right)$$

Since \frac{10\times 3}{3} and \frac{x}{3} have the same denominator, add them by adding their numerators.

$$\left(48-x\right)\times \frac{10\times 3+x}{3}$$

Do the multiplications in 10\times 3+x.

$$\left(48-x\right)\times \frac{30+x}{3}$$

Express \left(48-x\right)\times \frac{30+x}{3} as a single fraction.

$$\frac{\left(48-x\right)\left(30+x\right)}{3}$$

Apply the distributive property by multiplying each term of 48-x by each term of 30+x.

$$\frac{1440+48x-30x-x^{2}}{3}$$

Combine 48x and -30x to get 18x.

$$\frac{1440+18x-x^{2}}{3}$$

Expand

$$-\frac{x^{2}}{3}+6x+480$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 10 times \frac{3}{3}.

$$\left(48-x\right)\left(\frac{10\times 3}{3}+\frac{x}{3}\right)$$

Since \frac{10\times 3}{3} and \frac{x}{3} have the same denominator, add them by adding their numerators.

$$\left(48-x\right)\times \frac{10\times 3+x}{3}$$

Do the multiplications in 10\times 3+x.

$$\left(48-x\right)\times \frac{30+x}{3}$$

Express \left(48-x\right)\times \frac{30+x}{3} as a single fraction.

$$\frac{\left(48-x\right)\left(30+x\right)}{3}$$

Apply the distributive property by multiplying each term of 48-x by each term of 30+x.

$$\frac{1440+48x-30x-x^{2}}{3}$$

Combine 48x and -30x to get 18x.

$$\frac{1440+18x-x^{2}}{3}$$