Solve (428-x)div16*25=30

$$(428-x) \div 16 \times 25=30$$

Solve for x

$$x = \frac{2044}{5} = 408\frac{4}{5} = 408.8$$

Steps for Solving Linear Equation

Divide both sides by 25.

$$\frac{428-x}{16}=\frac{30}{25}$$

Reduce the fraction \frac{30}{25} to lowest terms by extracting and canceling out 5.

$$\frac{428-x}{16}=\frac{6}{5}$$

Multiply both sides by 16.

$$428-x=\frac{6}{5}\times 16$$

Express \frac{6}{5}\times 16 as a single fraction.

$$428-x=\frac{6\times 16}{5}$$

Multiply 6 and 16 to get 96.

$$428-x=\frac{96}{5}$$

Subtract 428 from both sides.

$$-x=\frac{96}{5}-428$$

Convert 428 to fraction \frac{2140}{5}.

$$-x=\frac{96}{5}-\frac{2140}{5}$$

Since \frac{96}{5} and \frac{2140}{5} have the same denominator, subtract them by subtracting their numerators.

$$-x=\frac{96-2140}{5}$$

Subtract 2140 from 96 to get -2044.

$$-x=-\frac{2044}{5}$$

Multiply both sides by -1.

$$x=\frac{2044}{5}$$